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x^2+1.95x+.75=0
We add all the numbers together, and all the variables
x^2+1.95x+0.75=0
a = 1; b = 1.95; c = +0.75;
Δ = b2-4ac
Δ = 1.952-4·1·0.75
Δ = 0.8025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.95)-\sqrt{0.8025}}{2*1}=\frac{-1.95-\sqrt{0.8025}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.95)+\sqrt{0.8025}}{2*1}=\frac{-1.95+\sqrt{0.8025}}{2} $
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